(2y-7)(3y^2+y-5)=x

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Solution for (2y-7)(3y^2+y-5)=x equation: 


Simplifying
(2y + -7)(3y2 + y + -5) = x

Reorder the terms:
(-7 + 2y)(3y2 + y + -5) = x

Reorder the terms:
(-7 + 2y)(-5 + y + 3y2) = x

Multiply (-7 + 2y) * (-5 + y + 3y2)
(-7(-5 + y + 3y2) + 2y * (-5 + y + 3y2)) = x
((-5 * -7 + y * -7 + 3y2 * -7) + 2y * (-5 + y + 3y2)) = x
((35 + -7y + -21y2) + 2y * (-5 + y + 3y2)) = x
(35 + -7y + -21y2 + (-5 * 2y + y * 2y + 3y2 * 2y)) = x
(35 + -7y + -21y2 + (-10y + 2y2 + 6y3)) = x

Reorder the terms:
(35 + -7y + -10y + -21y2 + 2y2 + 6y3) = x

Combine like terms: -7y + -10y = -17y
(35 + -17y + -21y2 + 2y2 + 6y3) = x

Combine like terms: -21y2 + 2y2 = -19y2
(35 + -17y + -19y2 + 6y3) = x

Solving
35 + -17y + -19y2 + 6y3 = x

Solving for variable 'y'.

Reorder the terms:
35 + -1x + -17y + -19y2 + 6y3 = x + -1x

Combine like terms: x + -1x = 0
35 + -1x + -17y + -19y2 + 6y3 = 0

The solution to this equation could not be determined.

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